AlgebraIntermediate

Quadratic Equations

A quadratic equation has the form ax² + bx + c = 0. It can have zero, one, or two real solutions. The parabola it describes is one of the most common curves in nature and physics , from the path of a thrown ball to satellite dish shapes.

✔ Quick Answer , How to Solve a Quadratic Equation

For ax² + bx + c = 0, use the quadratic formula: x = (−b ± √(b² − 4ac)) ÷ 2a. Or factor if possible: find two numbers that multiply to ac and add to b. Example: x² + 5x + 6 = 0 factors to (x+2)(x+3) = 0, giving x = −2 or x = −3.

1 What Makes an Equation Quadratic

A quadratic equation is any equation that can be written in the form ax² + bx + c = 0, where a ≠ 0. The highest power of x is 2. Examples: x² − 5x + 6 = 0, 2x² + 3x = 0, x² = 16.

Quadratics can have up to two solutions (also called roots or zeros) because a parabola can cross the x-axis at 0, 1, or 2 points. Understanding all three methods for solving them gives you flexibility for any situation.

2 Method 1: Solving by Factoring

If the quadratic factors nicely, this is the fastest method. The logic is simple: if two things multiply to zero, at least one of them must be zero. So you factor, set each piece to zero, and solve each one.

Solving by Factoring
Solve: x² + 5x + 6 = 0
1Factor the left side: (x + 2)(x + 3) = 0
2Set each factor to zero: x + 2 = 0 → x = −2
3And: x + 3 = 0 → x = −3
4Check x=−2: (−2)²+5(−2)+6 = 4−10+6 = 0 ✓
Answer: x = −2 or x = −3

3 Method 2: The Quadratic Formula

The quadratic formula always works, no matter what. Even when the numbers are ugly and factoring is hopeless: x = (−b ± √(b² − 4ac)) / 2a

Using the Quadratic Formula
Solve: 2x² − 4x − 6 = 0
1Identify a=2, b=−4, c=−6
2b² − 4ac = (−4)² − 4(2)(−6) = 16 + 48 = 64
3x = (4 ± √64) / 4 = (4 ± 8) / 4
4x = (4+8)/4 = 3 OR x = (4−8)/4 = −1
Answer: x = 3 or x = −1
When to use the formula

Use the quadratic formula when: the equation doesn't factor nicely, the coefficients are large or decimal, or you need an exact answer for radicals. It always produces the correct answer.

4 Method 3: Completing the Square

Completing the square rewrites the quadratic in the form (x + h)² = k, then solves by taking the square root. This method is important for deriving the quadratic formula and for understanding vertex form of parabolas.

Completing the Square
Solve: x² + 6x + 5 = 0
1Move the constant: x² + 6x = −5
2Add (6/2)² = 9 to both sides: x² + 6x + 9 = −5 + 9 = 4
3Factor the perfect square: (x + 3)² = 4
4Take the square root: x + 3 = ±2
5x = −3 + 2 = −1 OR x = −3 − 2 = −5
Answer: x = −1 or x = −5

5 The Discriminant: Predicting Solutions

The expression under the square root in the quadratic formula , b² − 4ac , is called the discriminant. It tells you how many real solutions exist before you solve:

Discriminant outcomes
2b² − 4ac > 0: Two distinct real solutions. The parabola crosses the x-axis at two points.
1b² − 4ac = 0: Exactly one real solution (a repeated root). The parabola touches the x-axis at exactly one point.
0b² − 4ac < 0: No real solutions. The parabola doesn't cross the x-axis (solutions are complex numbers).

Try the Quadratic Formula Calculator

Enter a, b, and c , get both roots instantly with the discriminant shown.

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Practice Problems

Solve: x² − 7x + 12 = 0 by factoring
Factor: (x − 3)(x − 4) = 0. Solutions: x = 3 or x = 4
How many solutions does x² + 4x + 5 = 0 have?
Discriminant = 4² − 4(1)(5) = 16 − 20 = −4. Since discriminant < 0, there are no real solutions.
Solve: 3x² − 7x + 2 = 0 using the quadratic formula
a=3, b=−7, c=2. Discriminant = 49−24 = 25. x = (7±5)/6. x = 12/6 = 2 or x = 2/6 = 1/3.

Sources & Further Reading

The explanations on this page draw on the following established sources. We link to primary and secondary sources so you can verify claims and go deeper on any topic.